4+7x-3x^2=0

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Solution for 4+7x-3x^2=0 equation: 



4+7x-3x^2=0

a = -3; b = 7; c = +4;
Δ = b2-4ac
Δ = 72-4·(-3)·4
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{97}}{2*-3}=\frac{-7-\sqrt{97}}{-6}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{97}}{2*-3}=\frac{-7+\sqrt{97}}{-6}
$

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